JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Mechanical Properties of Solids

  • question_answer
    If the ratio of radii of two wires of same material is 3 : 1 and ratio of their lengths is 5 : 1, then the ratio of the normal forces that will produce the same extension in the length of two wires is

    A) 2:1 

    B) 4:1  

    C) 1:4 

    D) 1:1

    Correct Answer: D

    Solution :

    [d] \[Y=\frac{F\ell }{A\Delta \ell };\Rightarrow \,\,\,\,\,F=\frac{YA\Delta \ell }{\ell }\] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{A}_{1}}}{{{A}_{2}}}\times \frac{{{I}_{2}}}{{{I}_{1}}}=\frac{r_{1}^{2}}{r_{2}^{2}}\times \frac{{{I}_{2}}}{{{I}_{1}}}=\frac{4}{1}\times \frac{1}{4}=1:1.\]


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