A) \[7.1\times {{10}^{-8}}{{m}^{2}}\]
B) \[7.1\times {{10}^{-6}}{{m}^{2}}\]
C) \[7.1\times {{10}^{-4}}{{m}^{2}}\]
D) \[7.1\times {{10}^{-2}}{{m}^{2}}\]
Correct Answer: C
Solution :
[c] Maximum possible strain \[=0.2/100\] \[\therefore \,\,\,\,A=\frac{F}{Y\times strain}=\frac{{{10}^{4}}\times 100}{(7\times {{10}^{9}})\times 0.2}\] \[=7.1\times {{10}^{-4}}{{m}^{2}}\]
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