A) \[(1/4)\rho g{{L}^{2}}/Y\]
B) \[(1/2)\rho g{{L}^{2}}/Y\]
C) \[\rho g{{L}^{2}}/Y\]
D) \[\rho gL/Y\]
Correct Answer: B
Solution :
[b] \[\Delta \ell =\frac{F(L/2)}{AY}=\frac{(AL\rho g)(L/2)}{AY}\] \[=\left( \frac{1}{2} \right)\rho g{{L}^{2}}/Y\]You need to login to perform this action.
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