JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Mechanical Properties of Solids

  • question_answer
    The force exerted by a special compression device is given as function of compression x as \[{{F}_{x}}(x)=kx(x-\ell )\] for\[0\le x\le \ell \], where \[\ell \]is maximum possible compression and A: is a constant. The force exerted by the device under compression is maximum when compression is -

    A) 0

    B) \[\ell /4\] 

    C) \[\ell /\sqrt{2}\]

    D) \[\ell /2\]

    Correct Answer: D

    Solution :

    [d] \[\frac{dF}{dx}=0\,\,at\,\ell /2\]


You need to login to perform this action.
You will be redirected in 3 sec spinner