A) 0.0067%
B) 0.0098%
C) 0.0088%
D) 0.0078%
Correct Answer: B
Solution :
[b] Stress\[=\,kg\,wt/m{{m}^{2}}=9.8N/m{{m}^{2}}\] \[9.8\times {{10}^{6}}N/{{m}^{2}}\] \[Y=1\times {{10}^{11}}N/{{m}^{2}},\,\,\,\,\,\,\frac{\Delta \ell }{\ell }\times 100=?\] \[Y=\frac{Stress}{Strain}=\frac{Stress}{\Delta \ell /\ell }\] \[\therefore \,\,\frac{\Delta \ell }{\ell }=\frac{Stress}{Y}=\frac{9.8\times {{10}^{6}}}{1\times {{10}^{11}}}\] \[\frac{\Delta \ell }{\ell }\times 100=9.8\times {{10}^{-11}}\times 100\times {{10}^{6}}\] \[=9.8\times {{10}^{-3}}=0.0098%\]
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