A) \[4\times {{10}^{3}}N\]
B) \[16\times {{10}^{3}}N\]
C) \[\frac{1}{4}\times {{10}^{3}}N\]
D) \[\frac{1}{16}\times {{10}^{3}}N\]
Correct Answer: B
Solution :
[b] \[F=Y\times A\times \frac{l}{L}\Rightarrow F\propto {{r}^{2}}\](Y, l and L are constant) If diameter is made four times then force required will be 16 times, i.e., \[16\times {{10}^{3}}N\]
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