A) \[9\times {{10}^{-3}}J\]
B) \[12\times {{10}^{-3}}J\]
C) \[14\times {{10}^{-3}}J\]
D) \[16\times {{10}^{-3}}J\]
Correct Answer: C
Solution :
[c] \[\Delta w=\frac{1}{2}[{{F}_{2}}{{\ell }_{2}}-{{F}_{1}}{{\ell }_{1}}]\] \[\begin{align} & =\frac{1}{2}[4\times 10\times 1\times {{10}^{-3}}-2\times 10\times 0.6\times {{10}^{-3}} \\ & =14\times {{10}^{-3}}] \\ \end{align}\]You need to login to perform this action.
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