A) \[Y{{X}^{2}}\]
B) \[2Y{{X}^{2}}\]
C) \[{{Y}^{2}}X/2\]
D) \[Y{{X}^{2}}/2\]
Correct Answer: D
Solution :
[d] \[P.E.\text{ }=\frac{1}{2}\times \text{ }stress\text{ }\times \text{ }strain\text{ }\times \text{ }volume\] or \[\left( P.E./volume \right)\text{ }=\text{ }\frac{1}{2}\times \text{ }\left( Y\text{ }\times \text{ }strain \right)\text{ }\left( strain \right)\] \[=\frac{1}{2}Y{{(strain)}^{2}}=\frac{1}{2}Y{{X}^{2}}\]
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