2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Wave Mechanics

JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Mechanical Properties of Solids

  • question_answer
    When a force is applied on a wire of uniform cross-section area \[3\times {{10}^{-6}}{{m}^{2}}\] and length 4m, the increase in length is 1 mm. Energy stored in it will be (\[Y=2\times {{10}^{11}}N/{{m}^{2}}\])

    A) 6250J

    B) 0.177J

    C) 0.075 J

    D) 0.150J

    Correct Answer: C

    Solution :

    [c] \[e=\frac{\Delta Y}{\ell }=\frac{1\times {{10}^{-3}}}{4}\]        \[u=\frac{{{e}^{2}}y}{2}={{\left( \frac{{{10}^{-3}}}{4} \right)}^{2}}\times \frac{2\times {{10}^{11}}}{2}=0.075J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner