JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Mechanical Properties of Solids

  • question_answer
    Two parallel and opposite forces, each of magnitude 4000 N are applied tangentially to the upper and lower faces of a cubical metal block 25 cm on a side. The angle of Shear is [shear modulas of metal is 80 G Pa]

    A) \[8\times {{10}^{-7}}rad\]

    B) \[7\times {{10}^{-7}}rad\]

    C) \[6\times {{10}^{-6}}rad\]

    D) \[5\times {{10}^{-5}}ra\]

    Correct Answer: A

    Solution :

    [a] Shear stress \[=\frac{F}{A}\] \[\tan \theta =\frac{shear\,stress}{shear\,\bmod ulus}\] \[\Rightarrow \tan \theta =\frac{4000}{{{(0.25)}^{2}}\times 8\times {{10}^{10}}}\]     \[\tan \theta =8\times {{10}^{-7}}\] for small angle \[\tan \theta =\theta =8\times {{10}^{-7}}rad\]


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