JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Mechanical Properties of Solids

  • question_answer
    The Young's modulus of the material of a wire is \[2\times {{10}^{10}}N{{m}^{-2}}\]. If the elongation strain is 1 %, then the energy stored in the wire per unit volume in \[J{{m}^{-3}}\] is

    A) \[{{10}^{6}}\] 

    B) \[{{10}^{8}}\]

    C) \[2\times {{10}^{6}}\]

    D) \[2\times {{10}^{8}}\]

    Correct Answer: A

    Solution :

    [a] \[Y=2\times {{10}^{10}}N{{m}^{-2}};\frac{\Delta l}{l}=0.01\] Work done per unit volume \[=\frac{1}{2}\times stress\times strain=\frac{1}{2}\times Y\times strai{{n}^{2}}\] \[=\frac{1}{2}Y{{\left( \frac{\Delta l}{l} \right)}^{2}}\] \[\therefore \,\,U=\frac{1}{2}\times 2\times {{10}^{10}}\times {{\left( \frac{1}{100} \right)}^{2}}=U={{10}^{6}}J{{m}^{-3}}\]


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