A) 1:1
B) \[\text{tan}\theta :1\]
C) \[1:\text{tan}\theta \]
D) \[\text{ta}{{\text{n}}^{2}}\theta :1\]
Correct Answer: D
Solution :
[d] \[\frac{{{\text{H}}_{\text{1}}}}{{{\text{H}}_{\text{2}}}}\text{=}\frac{{{\text{u}}^{2}}{{\sin }^{2}}\theta /\text{2g}}{{{\text{u}}^{2}}{{\sin }^{2}}\left( 90{}^\circ -\theta \right)/2\text{g}}={{\tan }^{2}}\theta \]You need to login to perform this action.
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