A) \[\text{4}\,\text{m }{{\text{s}}^{-2}}\] along y-direction
B) \[\text{3}\,\text{m }{{\text{s}}^{-2}}\] along x-direction
C) \[\text{4 m }{{\text{s}}^{-2}}\] along x-direction
D) \[\text{2 m }{{\text{s}}^{-2}}\] along z-direction
Correct Answer: C
Solution :
[c] \[\text{\vec{r}}=2{{\text{t}}^{2}}\hat{i}+3t\hat{j}+4\hat{k}\] \[\therefore \text{\vec{v}=}\frac{d\vec{r}}{dt}=\frac{d}{dt}=\left( 2{{\text{t}}^{2}}\hat{i}+3t\hat{j}+4\hat{k} \right)=4\text{t}\hat{i}+3\hat{j}\] \[\text{\vec{a}=}\frac{d\text{\vec{v}}}{dt}=\frac{d}{dt}\left( 4\text{t}\hat{i}+3\hat{j} \right)=4\hat{i}\] \[\therefore \text{\vec{a}}=4m{{s}^{-2}}\text{ along x-direction}\]You need to login to perform this action.
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