A) 1440 km/h
B) 960 km/h
C) 1920 km/h
D) 480 km/h
Correct Answer: B
Solution :
[b] |
\[x=h\cot \theta \] |
\[\therefore \frac{dx}{dt}=h\frac{d\left( \cot \theta \right)}{dt}\] |
\[=h\,\,(-\,\text{cose}{{\text{c}}^{2}}\theta )\,\,\frac{d\theta }{dt}\] |
\[\text{or }\,v=h\text{ cose}{{\text{c}}^{2}}\theta \,\,\left( -\frac{d\theta }{dt} \right)\] |
\[=(8\times {{10}^{3}})\,\text{cose}{{\text{c}}^{2}}60{}^\circ \times 0.025=2666.67\text{ m/s}\] |
\[\text{=}\,\,\text{960 km/h}\] |
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