A) \[{{\pi }^{2}}\text{m}{{\text{s}}^{-2}}\] and direction along the radius towards the center.
B) \[{{\pi }^{2}}\text{m}{{\text{s}}^{-2}}\] and direction along the radius away from the center.
C) \[{{\pi }^{2}}\text{m}{{\text{s}}^{-2}}\] and direction along the tangent to the circle.
D) \[{{\pi }^{2}}\text{/4m}{{\text{s}}^{-2}}\] and direction along the radius towards the center.
Correct Answer: A
Solution :
[a] \[{{\text{a}}_{\text{r}}}-{{\omega }^{\text{2}}}\text{R}\] |
\[{{a}_{r}}={{\left( 2\pi 2 \right)}^{2}}R=4{{\pi }^{2}}{{2}^{2}}R\] |
\[\text{=}\,\text{4}{{\pi }^{2}}{{\left( \frac{22}{44} \right)}^{2}}\left( 1 \right)\text{ }\left[ \because \text{v}=\frac{22}{44} \right]\]. |
\[{{\text{a}}_{\text{t}}}\text{=}\frac{\text{dv}}{\text{dt}}=0\] |
\[{{a}_{net}}=\text{ }{{a}_{t}}={{\pi }^{2}}m{{s}^{-\,2}}\] and direction along the radius towards the center. |
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