A) \[\tan \alpha =\frac{8+10\sin \beta }{10\cos \beta }\]
B) \[\tan \beta =\frac{8+10\sin \alpha }{10\cos \alpha }\]
C) \[\tan \alpha =\tan \beta \]
D) \[\tan \alpha =\cot \beta \]
Correct Answer: B
Solution :
[b] \[\tan \beta =\frac{{{v}_{girl}}+{{v}_{rain}}\sin \alpha }{{{v}_{rain}}\cos \alpha }\] \[\Rightarrow \tan \beta =\frac{8+10\sin \alpha }{10\cos \alpha }\]You need to login to perform this action.
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