A) 2v
B) \[\sqrt{3}\text{v}\]
C) v
D) \[\frac{\text{v}}{\sqrt{3}}\]
Correct Answer: B
Solution :
[b] As the figure drawn above shows that at points A and B the vertical component of velocity is \[v\,\,\sin \,60{}^\circ \] but their directions are opposite. Hence, change in velocity. \[\Delta v=v\text{ }\sin 60{}^\circ -\left( -\,v\sin 60{}^\circ \right)=2v\,\,\sin 60{}^\circ =\sqrt{3}v\]You need to login to perform this action.
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