A) the time lapse for the two bodies to collide is \[\frac{6\pi \text{R}}{5\text{v}}\]
B) the angle covered by A is 11\[\pi \]/6
C) angular velocity of A is \[\frac{11\text{v}}{5\text{R}}\]
D) radial acceleration of A is \[\text{289 }{{\text{v}}^{\text{2}}}\text{/5R}\]
Correct Answer: B
Solution :
[b] As when they collide \[vt+\frac{1}{2}\left( \frac{77{{v}^{2}}}{25\pi R} \right){{t}^{2}}-\pi R=vt\] |
\[\therefore \,\,\text{t}=\frac{\text{5}\pi \text{R}}{\text{6v}}\] |
Now, angle covered by \[\text{A}=\pi +\frac{\text{vt}}{\text{R}}\] |
Put t, \[\therefore \text{ angle covered by A=}\frac{11\pi }{6}\] |
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