A) 1
B) \[\frac{1}{2}\]
C) \[\frac{1}{3}\]
D) 3
Correct Answer: C
Solution :
During OA, acceleration \[=\text{ }tan\text{ }30{}^\circ =sm/{{s}^{2}}\] During AB, acceleration \[=-tan\,60{}^\circ \] \[=-\sqrt{3}\text{ m/}{{\text{s}}^{2}}\] \[\text{Required ratio = }\frac{1/\sqrt{3}}{\sqrt{3}}=\frac{1}{3}\]
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