A) \[\frac{{{a}_{2}}}{3}\]
B) \[\frac{2{{a}_{2}}}{3}\]
C) \[\frac{{{a}_{1}}}{2}\]
D) \[{{a}_{0}}+\frac{{{a}_{2}}}{3}\]
Correct Answer: B
Solution :
\[\frac{dx}{dt}=\frac{{{a}_{t}}}{2}+\frac{2{{a}_{2}}}{3}\Rightarrow \frac{{{d}^{2}}x}{dt}=\frac{2{{a}_{2}}}{3}\] Acceleration requiredYou need to login to perform this action.
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