A) \[7.5\text{ }m/s\]
B) \[15\text{ }m/s\]
C) \[\text{20 }m/s\]
D) \[\text{5 }m/s\]
Correct Answer: B
Solution :
B catches C in time t then \[\text{t=}\frac{d}{u-10}\]. Separation by this time has increased by 'd' between A and C hence \[\left( 10-5 \right)\times \frac{d}{\left( u-10 \right)}=d,\text{ }u=15m/s\]
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