The total distance travelled by the body during the motion is equal to __.
A) \[\frac{\text{1}}{\text{2}}\left( \text{AD+BE} \right)\text{ }\!\!\times\!\!\text{ OC}\]
B) \[\frac{\text{1}}{\text{2}}\left( \text{OA+BC} \right)\text{ }\!\!\times\!\!\text{ OC}\]
C) \[\frac{\text{1}}{\text{2}}\left( \text{OC+AB} \right)\text{ }\!\!\times\!\!\text{ AD}\]
D) \[\frac{\text{1}}{\text{2}}\left( \text{OA+AB} \right)\text{ }\!\!\times\!\!\text{ BC}\]
Correct Answer: C
Solution :
distance travelled = area \[\square \text{OABC}\] \[=\frac{1}{2}\times \left( \text{OC+AB} \right)\times \text{AD}\]
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