A) square of the initial velocity
B) square of the initial acceleration
C) the initial velocity
D) the initial acceleration
Correct Answer: A
Solution :
Let s be the distance travelled by the vehicle before it stops. Final velocity \[v=0\], initial velocity = u Using equation of motion \[{{v}^{2}}-\text{ }{{\text{u}}^{\text{2}}}\text{= 2aS}\] \[{{0}^{2}}-\text{ }{{\text{u}}^{\text{2}}}\text{= 2aS}\] Stopping distance, \[\text{S }=-\frac{{{\text{u}}^{\text{2}}}}{\text{2a}}\]
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