JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Self Evaluation Test - Motion in a Strainght Line

  • question_answer
    If a train travelling at \[20\text{ }m/s\] is to be brought to rest in a distance of 200 m, then its retardation should be

    A) \[1\text{ }m/{{s}^{2}}\]

    B) \[2\text{ }m/{{s}^{2}}\]

    C) \[10\text{ }m/{{s}^{2}}\]

    D) \[20\text{ }m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

    \[{{v}^{2}}-\text{ }{{\text{u}}^{\text{2}}}\text{= 2aS}\] \[\Rightarrow a=\frac{{{\text{u}}^{\text{2}}}\text{ }}{\text{2aS}}=\frac{{{\left( 20 \right)}^{2}}}{2\times 200}=1m/{{s}^{2}}\]


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