A) 6 m
B) 4 m
C) \[\frac{10}{3}\,m\]
D) \[\frac{19}{3}\,m\]
Correct Answer: C
Solution :
Distance travelled in the nth second is given by \[{{t}_{n}}=u+\frac{a}{2}\left( 2n-1 \right)\] \[\text{Put u=0, a=}\frac{4}{3}m{{s}^{-2}},\]\[n=3\] \[\therefore d=0+\frac{4}{3\times 2}\left( 2\times 3-1 \right)=\frac{4}{6}\times 5=\frac{10}{3}m\]
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