A) 2880 m
B) 1440 m
C) 400 m
D) 20 m
Correct Answer: C
Solution :
Initial velocity of car (u) = 0 Final velocity of car \[\left( v \right)=144\text{ }km/hr=40\text{ }m/s\] Time taken = 20s We know that, \[v\text{ }=\text{ }u\text{ }+\text{ }at\]\[40=a\times 20\Rightarrow a=2\text{ m/}{{\text{s}}^{2}}\text{.}\] \[\text{Also, }{{\text{v}}^{2}}-{{u}^{2}}=2as\Rightarrow s=\frac{{{\text{v}}^{2}}-{{u}^{2}}}{2a}\] \[\Rightarrow s=\frac{{{\left( 40 \right)}^{2}}-{{\left( 0 \right)}^{2}}}{2\times 2}=\frac{1600}{4}=400\text{ m}\]
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