A) 5 m/s
B) 10 m/s
C) 12 m/s
D) 15 m/s
Correct Answer: D
Solution :
\[{{\text{V}}_{\max }}=0+5{{t}_{1}}\text{ }....\text{(i)}\] \[\text{0=}{{\text{V}}_{\max }}-3{{t}_{2}}\text{ }....\text{(ii)}\] \[\Rightarrow {{t}_{1}}+{{t}_{2}}=8={{V}_{\max }}\left( \frac{1}{5}+\frac{1}{3} \right)\] \[\Rightarrow {{\text{V}}_{\max }}=\frac{8\times 15}{8}=15\text{ m/s}\]
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