A) \[\text{S=}\frac{\text{1}}{\text{6}}\text{f}{{\text{t}}^{\text{2}}}\]
B) \[\text{S=ft}\]
C) \[\text{S=}\frac{\text{1}}{\text{4}}\text{f}{{\text{t}}^{\text{2}}}\]
D) \[\text{S=}\frac{\text{1}}{\text{72}}\text{f}{{\text{t}}^{\text{2}}}\]
Correct Answer: D
Solution :
Distance from A to B = \[S=\frac{1}{2}f{{t}_{1}}^{{}}\] Distance from B to C = \[\left( f{{t}_{1}} \right)t\] Distance from C to D = \[\frac{{{u}^{2}}}{2a}=\frac{{{\left( f{{t}_{1}} \right)}^{2}}}{2\left( f/2 \right)}\] \[f{{t}_{1}}^{2}=2S\]You need to login to perform this action.
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