A) \[0\]
B) \[-2\text{ }m/s\]
C) \[-4\text{ }m/s\]
D) \[\text{8 }m/s\]
Correct Answer: A
Solution :
\[\text{v}=4t-3{{t}^{2}}\] \[{{V}_{avg}}=\frac{0-0}{2}=0\] \[{{V}_{avg}}=\frac{{{s}_{\left( 2 \right)}}-{{s}_{\left( 0 \right)}}}{2-0}\left[ {{s}_{2}}=8-8=0 \right]\] \[{{V}_{avg}}=\frac{0-0}{2}=0\]
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