A) 1.5 units, 4 units
B) 3 units, 4 units
C) 16 units, 1.6 units
D) 16 units, 3 units
Correct Answer: A
Solution :
\[\text{v=}\sqrt{3x+16}\Rightarrow {{\text{v}}^{2}}=3x+16\] \[\Rightarrow {{v}^{2}}-16=3x\] Comparing with \[{{v}^{2}}-{{u}^{2}}=\text{ }2aS\], we get, \[u=4\]units, \[2a=3\]or \[a=1.5\text{ }units\]
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