A) \[{{s}_{2}}={{s}_{1}}\]
B) \[{{s}_{2}}=2{{s}_{1}}\]
C) \[{{s}_{2}}=3{{s}_{1}}\]
D) \[{{s}_{2}}=4{{s}_{1}}\]
Correct Answer: C
Solution :
Let a be the constant acceleration of the particle. Then \[\text{s=ut+}\frac{\text{1}}{\text{2}}\text{a}{{\text{t}}^{\text{2}}}\] or \[{{\text{s}}_{\text{1}}}\text{=0+}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ a }\!\!\times\!\!\text{ }{{\left( \text{10} \right)}^{\text{2}}}\text{=50 a}\] and \[{{\text{s}}_{2}}=\left[ \text{0+}\frac{\text{1}}{\text{2}}\text{a}{{\left( \text{20} \right)}^{\text{2}}} \right]-\text{50a=150a}\] \[\therefore {{s}_{2}}=3{{s}_{1}}\]
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