A) \[\frac{1}{2}g{{t}_{1}}{{t}_{2}}\]
B) \[g\,{{t}_{1}}{{t}_{2}}\]
C) \[2g\,{{t}_{1}}{{t}_{2}}\]
D) \[2hg\]
Correct Answer: A
Solution :
\[h=u{{t}_{1}}-\frac{1}{2}g{{t}_{1}}^{2}\] \[\text{Also h=u}{{\text{t}}_{2}}-\frac{1}{2}g{{t}_{2}}^{2}\] After simplify above equations, we get \[h=\frac{1}{2}g{{t}_{1}}{{t}_{2.}}\]
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