A) velocity A is more than B at the ground
B) velocity of B is more than A at the ground
C) both A & B strike the ground with same velocity
D) None of these
Correct Answer: C
Solution :
If A is the height of the building, then \[\text{v}_{\text{A}}^{\text{2}}\text{=}{{\text{v}}^{\text{2}}}\text{+2gh and v}_{B}^{2}={{\left( -\text{v} \right)}^{2}}+\text{2gh}\] Clearly \[{{\text{v}}_{\text{A}}}\text{= }{{\text{v}}_{\text{B}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
