A) \[{{\text{v}}_{\text{T}}}\text{+}{{\text{v}}_{\text{B}}}\text{=12m}{{\text{s}}^{-1}}\]
B) \[{{\text{v}}_{\text{T}}}-{{\text{v}}_{\text{B}}}=4.9\text{m}{{\text{s}}^{-1}}\]
C) \[{{\text{v}}_{\text{B}}}{{\text{v}}_{\text{T}}}\text{=1m}{{\text{s}}^{-1}}\]
D) \[{{\text{v}}_{\text{B}}}\text{/}{{\text{v}}_{\text{T}}}\text{=1m}{{\text{s}}^{-1}}\]
Correct Answer: B
Solution :
\[\text{v}_{\text{B}}^{\text{2}}\text{=v}_{\text{T}}^{\text{2}}\text{+2}\left( \text{10} \right)\left( \text{3} \right)\] \[\Rightarrow \text{v}_{\text{B}}^{\text{2}}\text{=v}_{\text{T}}^{\text{2}}\text{+60 }....\text{(i)}\] \[\text{Also, }{{\text{v}}_{B}}={{\text{v}}_{T}}+\left( 10 \right)\left( 0.5 \right)\text{ }....\text{(ii)}\] Solve eqs. (i) and (ii) We get \[{{\text{v}}_{T}}-{{\text{v}}_{B}}=4.9\text{ m/s}\]You need to login to perform this action.
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