A) \[\frac{h}{9}\]
B) \[\frac{7h}{9}\]
C) \[\frac{8h}{9}\]
D) \[\frac{17h}{18}\]
Correct Answer: C
Solution :
In \[\frac{\text{T}}{\text{3}}\] sec, the distance travelled =\[\frac{\text{1}}{\text{2}}\text{g}{{\left( \frac{\text{T}}{\text{3}} \right)}^{\text{2}}}\text{=}\frac{\text{h}}{\text{9}}\] \[\therefore \]Position of the ball from the ground =\[h-\frac{h}{9}=\frac{8h}{9}\text{m}\]
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