question_answer

A body thrown vertically so as to reach its maximum height in t second. The total time from the time of projection to reach a point at half of its maximum height while returning (in sec) is

A) \[\sqrt{\text{2}}\text{t}\]           

B) \[\left( \text{1+}\frac{\text{1}}{\sqrt{\text{2}}} \right)\text{t}\]

C) \[\frac{\text{3t}}{\text{2}}\]                  

D) \[\frac{\text{t}}{\sqrt{\text{2}}}\]