JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Self Evaluation Test - Motion in a Strainght Line

  • question_answer
    A body A is thrown vertically upward with the initial velocity \[{{v}_{1}}\]. Another body B is dropped from a height h. Find how the distance x between the bodies depends on the time t if the bodies begin to move simultaneously.

    A) \[x=h-{{v}_{1}}t\]

    B) \[x=\left( h-{{v}_{1}} \right)t\]

    C) \[x=h-\frac{{{v}_{1}}}{t}\]

    D) \[x=\frac{h}{t}-{{v}_{1}}\]

    Correct Answer: A

    Solution :

    The distance travelled by the body A is A, given by \[{{v}_{1}}t=-\frac{g{{t}^{2}}}{2}\] and that travelled by the body B is \[{{\text{h}}_{2}}=\frac{g{{t}^{2}}}{2}\]s The distance between the bodies \[=x=h-({{h}_{1}}+{{h}_{2}}).\] Since\[{{\text{h}}_{\text{1}}}\text{+}{{\text{h}}_{\text{2}}}\text{=}{{\text{v}}_{\text{1}}}\text{t}\], the relation sought is \[x=h-{{v}_{1}}t\]


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