JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Self Evaluation Test - Motion in a Strainght Line

  • question_answer
    A body is thrown upwards. If air resistance causing deceleration of \[5\text{ }m/{{s}^{2}}\], then ratio of time of ascent to time of descent is \[[take\text{ }g=10\text{ }m/{{s}^{2}}]\]

    A) \[\sqrt{\frac{1}{2}}\]                 

    B) \[\sqrt{\frac{1}{2.5}}\]

    C) \[\sqrt{\frac{1}{3}}\]                 

    D) \[\sqrt{\frac{1}{5}}\]

    Correct Answer: C

    Solution :

    \[\frac{\text{ }\!\!~\!\!\text{ Time of ascent}}{\text{Time of descent}}=\frac{\left( \frac{u}{g+a} \right)}{\frac{u}{\sqrt{\left( g+a \right)\left( g-a \right)}}}\] \[=\frac{\sqrt{\left( g+a \right)\left( g-a \right)}}{g+a}=\sqrt{\frac{\left( g-a \right)}{g+a}}\] \[=\sqrt{\frac{10-5}{10+5}}=\sqrt{\frac{5}{15}}=\sqrt{\frac{1}{3}}\]


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