JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Self Evaluation Test - Moving Charges and Mangetism

  • question_answer
    A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B. The time taken by the particle to complete one revolution is

    A) \[\frac{2\pi {{q}^{2}}B}{m}\]

    B) \[\frac{2\pi mq}{B}\]

    C) \[\frac{2\pi m}{qB}\]

    D) \[\frac{2\pi qB}{m}\]

    Correct Answer: C

    Solution :

    [c] Equating magnetic force to centripetal force, [a] \[\frac{m{{v}^{2}}}{r}=qvB\,\sin \,{{90}^{o}}\]    Time to complete one revolution, \[T=\frac{2\pi r}{v}=\frac{2\pi m}{qB}\]


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