A) \[{{t}_{He}}>{{t}_{p}}={{t}_{e}}\]
B) \[{{t}_{He}}>{{t}_{p}}>{{t}_{e}}\]
C) \[{{t}_{He}}={{t}_{p}}={{t}_{e}}\]
D) None of these
Correct Answer: B
Solution :
[b] \[T=2\pi m/qB\], \[{{\left( \frac{m}{q} \right)}_{He}}>{{\left( \frac{m}{q} \right)}_{p}}>{{\left( \frac{m}{q} \right)}_{e}}\] \[\therefore \,\,\,\,{{t}_{He}}>{{t}_{p}}>{{t}_{e}}\]
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