A) the velocity
B) the momentum
C) the kinetic energy
D) None of these
Correct Answer: C
Solution :
[c] As \[r=\frac{mv}{qB}=\frac{P}{qB}\] \[\therefore \,\,\,\]Area, \[A=\pi {{r}^{2}}=\pi {{\left( \frac{P}{qB} \right)}^{2}}=\frac{\pi {{p}^{2}}}{qB}=\frac{2m\pi }{qB}K\]
You need to login to perform this action.
You will be redirected in
3 sec
