A) Zero
B) \[3.2\,N\]
C) \[3.2\,\times {{10}^{-16}}N\]
D) \[1.6\,\times {{10}^{-16}}N\]
Correct Answer: C
Solution :
[c] Given: Magnetic field B\[=2\times {{10}^{-4}}\,weber/{{m}^{2}}\] Velocity of electron, \[v={{10}^{7}}\,m/s\] Lorentz force \[F=qvB\,\sin \,\theta \] \[=1.6\times {{10}^{-19}}\times {{10}^{7}}\times 2\times {{10}^{-4}}\] \[\left( \because \,\,\theta ={{90}^{o}} \right)\] \[=3.2\times {{10}^{-16}}N\]You need to login to perform this action.
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