A) 0.001
B) 0.01
C) 1
D) 0.05
Correct Answer: A
Solution :
[a] Galvanometer is converted into ammeter, by connected a shunt, in parallel with it. \[\frac{GS}{G+S}=\frac{{{V}_{G}}}{I}=\frac{25\times {{10}^{{{L}_{3}}}}}{25}\] \[\frac{GS}{G+S}=0.001\Omega \] Here \[S<<G\] so \[S=0.001\Omega \]You need to login to perform this action.
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