A) \[\left( \frac{{{v}_{0}}}{2{{B}_{0}}\alpha },\frac{\sqrt{2}{{v}_{0}}}{\alpha {{B}_{0}}},\frac{-{{v}_{0}}}{{{B}_{0}}\alpha } \right)\]
B) \[\left( \frac{-{{v}_{0}}}{2{{B}_{0}}\alpha },0,0 \right)\]
C) \[\left( 0,\frac{2{{v}_{0}}}{{{B}_{0}}\alpha },\frac{{{v}_{0}}\pi }{2{{B}_{0}}\alpha } \right)\]
D) \[\left( \frac{{{v}_{0}}\pi }{{{B}_{0}}\pi },0\frac{-2{{v}_{0}}}{{{B}_{0}}\alpha } \right)\]
Correct Answer: D
Solution :
[d] \[\alpha =\frac{q}{m}\], path of the particle will be a helix of time period,You need to login to perform this action.
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