A) \[\frac{{{\mu }_{0}}I\theta }{4\pi r}\]
B) \[\frac{{{\mu }_{0}}I\theta }{2\pi r}\]
C) \[\frac{{{\mu }_{0}}I\theta }{2r}\]
D) \[\frac{{{\mu }_{0}}I\theta }{4r}\]
Correct Answer: A
Solution :
[a] \[B=\frac{{{\mu }_{0}}I}{2r}\times \frac{\theta }{2\pi }=\frac{{{\mu }_{0}}I\theta }{4\pi r}\]
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