A) \[\frac{{{\mu }_{0}}}{2\pi d}\left( \frac{{{I}_{1}}}{{{I}_{2}}} \right)\]
B) \[\frac{{{\mu }_{0}}}{2\pi d}\left( {{I}_{1}}+{{I}_{2}} \right)\]
C) \[\frac{{{\mu }_{0}}}{2\pi d}\left( I_{1}^{2}-I_{2}^{2} \right)\]
D) \[\frac{{{\mu }_{0}}}{2\pi d}{{\left( I_{1}^{2}\times I_{2}^{2} \right)}^{1/2}}\]
Correct Answer: D
Solution :
[d] Net magnetic field, \[B=\sqrt{B_{1}^{2}+B_{2}^{2}}\] \[=\sqrt{{{\left( \frac{{{\mu }_{0}}{{I}_{1}}}{2\pi d} \right)}^{2}}+{{\left( \frac{{{\mu }_{0}}{{I}_{2}}}{2\pi d} \right)}^{2}}}=\frac{{{\mu }_{0}}}{2\pi d}\sqrt{I_{1}^{2}+I_{2}^{2}}\]
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