A) \[8\times {{10}^{-7}}N\]
B) \[8\times {{10}^{-5}}N\]
C) \[4\times {{10}^{-7}}N\]
D) \[4\times {{10}^{-5}}N\]
Correct Answer: B
Solution :
[b] \[F=\frac{{{\mu }_{0}}}{4\pi }\,\frac{2{{I}_{1}}{{I}_{2}}}{r}\times \ell \] \[=\frac{{{10}^{-7}}\times 2\times 10\times 2}{0.1}\times 2=8\times {{10}^{-5}}N\]
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