A) \[\sqrt{\frac{Bir}{m}}\]
B) \[\sqrt{\frac{Bir}{2m}}\]
C) \[\sqrt{\frac{2Bir}{m}}\]
D) \[2\sqrt{\frac{Bir}{m}}\]
Correct Answer: A
Solution :
[a] \[F\,\,\,\,\,\,\,=\,\,\,\,\,\,\,\,Bi\ell \] \[2T\,\sin \frac{\theta }{2}=F\]You need to login to perform this action.
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