question_answer

A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

A) 0.001   

B) 0.01  

C) 1         

D) 0.05

Correct Answer: A

Solution :

[a] Galvanometer is converted into ammeter, by connected a shunt, in parallel with it. \[\frac{GS}{G+S}=\frac{{{V}_{G}}}{I}=\frac{25\times {{10}^{{{L}_{3}}}}}{25}\] \[\frac{GS}{G+S}=0.001\Omega \] Here  \[S<<G\] so \[S=0.001\Omega \]