A) 0.495 ohm
B) 49.5 dim
C) 495 ohm
D) 4950 ohm
Correct Answer: C
Solution :
[c] \[{{I}_{g}}=10\times {{10}^{-3}}/5=2\times {{10}^{-3}}A;\] \[R=\frac{V}{{{I}_{g}}}-{{R}_{g}}=\frac{1}{2\times {{10}^{-3}}}-5=495\Omega \].
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